What is the current row in a list

[Greg Osenbach]

Thank you for explaining that so clearly David.  That helps me out a lot.
As it is, I am a LabVIEW programmer and I do have to admit that my text
based programming is a little rusty from many years of disuse  :)

I will take another crack at this now and let you all know how it goes.  I
eventually gave up last night about midnight in frustration at nothing
working how I intended it.  I am sure lack of sleep may have been a factor.
:)

Cheers,
Greg

On Mon, Feb 23, 2009 at 2:42 PM, David McFarlane <mcfarla9 at msu.edu> wrote:

>
> At 2/23/2009 12:02 AM Monday, Peter Quain wrote:
> >i spose you could add an attribute to your list(s) .. say called
> >'lstsample' and number sequentially.. and then grab that value
> >sss = [ListName].GetCurrentAttrib("lstsample")
>
> Yes, even I shot my mouth off a little too soon (I was at home over
> breakfast, now I made it to my work site).  Peter actually has the
> most serviceable answer here, although there is a slightly slicker
> approach that may work.  And the previous answers using ".Sample" are
> not strictly correct, although it may by accident work in some
> cases.  Let me explain.
>
> Suppose you have a List named List1.  When you run that list, you
> will find three related columns in the resulting .edat file:  List1,
> List1.Cycle, and List1.Sample.  If you only run one cycle of List1,
> *and* run in sequential order, *then* List1.Cycle will always show 1,
> and List1 will always equal List1.Sample.  However, if you run in
> random order, List1.Cycle will still always show 1 *but* List1 will
> only equal List1.Sample in the event that the "random" order turns
> out to be sequential, otherwise the values in these two attributes
> will differ -- List1.Sample will always show sequential values,
> whereas List1 will show which random row of List1 was selected for
> that iteration of the list.  Finally, if you run for more than one
> cycle, then, regardless of whether you use sequential or random
> selection, List1.Cycle will show which cycle of the list is running,
> and after cycle 1 then List1 will *never* equal List1.Sample -- i.e.,
> List1.Sample will continue to increase sequentially, while List1
> again shows which row of the list was selected for that iteration of the
> list.
>
> Whew!  So how do we summarize all that?
> - The attribute "List1" shows which row of the list has been selected
> for the current iteration of List1.
> - The attribute "List1.Cycle" shows which repetition of List1 in in
> progress.
> - The attribute "List1.Sample" shows how many times we have taken a
> sample from List1 so far.  (This attribute is always strictly
> increasing, and in some cases could be used for a built-in trial
> counter, though in general you would to better using your own script
> variable for that.)
>
> So, after all that, Greg could use something like
> sss = c.GetAttrib("MyList")
>
> (There are even fancier things you can to with casting functions in
> case you don't know what list name will be used and want to determine
> that programmatically at run time.  But that is far too advanced a topic.)
>
> But I really prefer Peter's answer, since it is a little clearer
> (insofar as it relies a little less on deep understanding of E-Prime
> lists and attributes) and allows for more control and flexibility.
>
> And please, as always do not take my word for any of this!  I insist
> that you to construct your own demonstration programs and test this
> for yourselves.
>
> My apologies to all for not getting this right the first time, and
> for once again posting a lengthy explanation,
> -- David McFarlane, Professional Faultfinder
>
>
> >
>

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