response recording during several displays
Aad Pors
aadpors at gmail.com
Mon Aug 18 11:41:23 UTC 2014
I have a stimulus screen that lasts for 250 ms, followed by a mask of 900
ms. The total response time (Time Limit) is 1150 ms. However, it does not
work, and I cannot figure out why. See attachment for the studio file...
Op donderdag 17 december 2009 19:15:48 UTC+1 schreef Sravani Vinapamula:
>
> Oh... Thank you! I will definitely look at the Appendix C
>
> On Thu, Dec 17, 2009 at 12:57 PM, David McFarlane <mcfa... at msu.edu
> <javascript:>> wrote:
>
>> Indeed, that is not a bad solution, and it is the first solution that
>> all my students come up with when I pose the question to them (and
>> was my own first solution). But for one thing it does seem
>> kludgy: The .RT appears sometimes in the stimulus column, sometimes
>> in the mask column, and when it appears in the mask column you have
>> to add in the duration of the stim. And if you do just that, your RT
>> will *not* include the time between the offset of the stimulus and
>> the onset of the mask. So to get it right when the response comes
>> during the mask you would need to calculate mask.RTTime -
>> stim.OnsetTime. Whew!
>>
>> There has to be an easier way, and there is -- *Extended
>> Input*. Extended input cleanly, simply, and transparently takes care
>> of all of this. Please please do not overlook Appendix C.
>>
>> -- David McFarlane, Professional Faultfinder
>>
>>
>> At 12/17/2009 11:32 AM Thursday, Sravani Vinapamula wrote:
>> >I think you can just give the duration for the response as the sum
>> >of the times of both slides.
>> >
>> >
>> >
>> >
>> >On Wed, Dec 16, 2009 at 4:23 AM, Tobi
>> ><<mailto:tobi... at gmail.com <javascript:>>tobias.fw at gmail.com
>> <javascript:>> wrote:
>> >Hi everyone,
>> >
>> >I have the following, although sounding simple, hard to solve problem:
>> >
>> >I want to show a stimulus for x ms and then to show a mask for y ms.
>> >Participants should be able to respond for the x+y ms, i.e. during two
>> >displays.
>> >
>> >How can I do this?
>> >Any hints are most welcome!
>> >
>> >Cheers,
>> >Tobias
>>
>> --
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>>
>
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