LL-L "Syntax" 2004.04.29 (03) [E]
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Thu Apr 29 23:10:03 UTC 2004
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A=Afrikaans Ap=Appalachian B=Brabantish D=Dutch E=English F=Frisian
L=Limburgish LS=Lowlands Saxon (Low German) N=Northumbrian
S=Scots Sh=Shetlandic V=(West)Flemish Z=Zeelandic (Zeêuws)
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From: Jan Strunk <strunkjan at hotmail.com>
Subject: LL-L "Syntax" 2004.04.29 (02) [E]
Hello,
Ron, thank you very much for the examples.
I have two more follow-up questions and then I hope that I can stop bugging
you.
Again all Low Saxon speakers are invited to answer...
Ron wrote:
> (*)Hinnerks öldsten Kinner vun Hinnerk
> Hinnerk sien öldsten Kinner
> (Hinnerk's oldest chidren.)
Does this get better if you use the following?
"Hinnerks öldste Kinner"
"mien Vadders öldste Kinner"
The second question is, whether the following is possible:
"All den Mann siene Kinner sünd nu al groot".
"All mien Vadder siene Frünne sünd kamen."
Beste gröten!
Jan Strunk
jstrunk at stanford.edu
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From: R. F. Hahn <sassisch at yahoo.com>
Subject: Syntax
Jan,
> (*)Hinnerks öldsten Kinner vun Hinnerk
Sorry. This was an error. (I must have gone wild pasting ...) It was
supposed to be this:
(*)Hinnerks öldsten Kinner
> Does this get better if you use the following?
> "Hinnerks öldste Kinner"
> "mien Vadders öldste Kinner"
Hmmm ... not quite, not in *my* book. The adjectival suffix _-e_ can only
be used in case of indefinite plural forms; e.g. _öldste Kinner_ '(some/any)
oldest children' (as opposed to definite _de öldsten Kinner_ 'the oldest
children'). All definite cases take the plural suffix _en_, and this
includes _mien öldsten Kinner_ 'my oldest children', not *_mien öldste
Kinner_), (*) _Hinnerks öldsten Kinner_ ~ _Hinnerk sien öldsten Kinner_
'Hinnerk's oldest children'.
I'm not totally sure with regard to the constructions with genitive _-s_.
They sound barely marginally acceptable with _-e_ with _Hinnerk_ and _mien
Vadder_, not with _mien_, perhaps a tad better than with _-en_, and I'm not
sure why. As I said, this is too marginal for me anyway. I would always
use constructions with X sien Y or Y vun X.
I hope this helps.
Reinhard/Ron
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